24x^2+48x-30=0

Solution for 24x^2+48x-30=0 equation:

24x^2+48x-30=0

a = 24; b = 48; c = -30;
Δ = b2-4ac
Δ = 482-4·24·(-30)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-72}{2*24}=\frac{-120}{48}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+72}{2*24}=\frac{24}{48}
=1/2
$